(3 points) A news report states that the 90% confidence interval for the mean number of...
2) (3 points) A news report states that the 90% confidence interval for the mean number of daily calories consumed by participants in a medical study is (2020, 2160). Assume the population distribution for daily calories consumed is normally distributed and that the confidence interval was based on a simple random sample of 20 observations. Calculate the sample mean, the margin of error, and the sample standard deviation based on the stated confidence interval and the given sample size. Use...
(3 points) A news report states that the 90% confidence interval for the mean number of daily calories consumed by participants in a medical study is (1750, 1980). Assume the population distribution for daily calories consumed is normally distributed and that the confidence interval was based on a simple random sample of 18 observations. Calculate the sample mean, the margin of error, and the sample standard deviation based on the stated confidence interval and the given sample size. Use the...
(3 points) A news report states that the 90% confidence interval for the mean number of daily calories consumed by participants in a medical study is (1930, 2170). Assume the population distribution for daily calories consumed is normally distributed and that the confidence interval was based on a simple random sample of 15 observations. Calculate the sample mean, the margin of error, and the sample standard deviation based on the stated confidence interval and the given sample size. Use the...
(3 points) A news report states that the 99% confidence interval for the mean number of daily calories consumed by participants in a medical study is (1860, 2060). Assume the population distribution for daily calories consumed is normally distributed and that the confidence interval was based on a simple random sample of 16 observations. Calculate the sample mean, the margin of error, and the sample standard deviation based on the stated confidence interval and the given sample size. Use the...
(3 points) A news report states that the 99% confidence interval for the mean number of daily calories consumed by participants in a medical study is (1750, 1880). Assume the population distribution for daily calories consumed is normally distributed and that the confidence interval was based on a simple random sample of 20 observations. Calculate the sample mean, the margin of error, and the sample standard deviation based on the stated confidence interval and the given sample size. Use the...
A news report states that the 95% confidence interval for the mean number of daily calories consumed by participants in a medical study is (2030, 2200). Assume the population distribution for daily calories consumed is normally distributed and that the confidence interval was based on a simple random sample of 19 observations. Calculate the sample mean, the margin of error, and the sample standard deviation based on the stated confidence interval and the given sample size. Use the t distribution...
Use graphing calculator to explain answer please. Round results to the nearest 4 decimal places (3 points) A news report states that the 99% confidence interval for the mean number of daily calories consumed by participants in a medical study is (1870, 2120). Assume the population distribution for daily calories consumed is normally distributed and that the confidence interval was based on a simple random sample of 15 observations. Calculate the sample mean, the margin of error, and the sample...
If you could include an explanation that would be appreciated! Problem Value: 3 point(s). Problem Score: 0 %. Attempts Remaining: 3 attempts. (3 points) A news report states that the 99% confidence interval for the mean number of daily calories consumed by participants in a medical study is (1800, 1980). Assume the population distribution for daily calories consumed is normally distributed and that the confidence interval was based on a simple random sample of 21 observations. Calculate the sample mean,...
Suppose the 90% confidence interval for the mean SAT scores of applicants at a business college is given by [1,694, 1,836]. This confidence interval uses the sample mean and the sample standard deviation based on 25 observations. [You may find it useful to reference the t table.] What are the sample mean and the sample standard deviation used when computing the interval? (Round "t" value to 3 decimal places and “Sample mean” and "Sample standard deviation" to 2 decimal places.)
X6.2.9-TConstruct the indicated confidence interval for the population mean μ using the t-distribution. Assume the population is normally distributed c = 0.90, x̅ = 12.9, s = 4.0, n = 9 The 90% confidence interval using a t-distribution is 6.2.17-T In a random sample of 26 people, the mean commute time to work was 34.8 minutes and the standard deviation was 7.2 minutes. Assume the population is normally distributed and use a t-distribution to construct a 98% confidence interval for the population mean μ...