If the potential of a Zn-H+ cell (see below) is 0.45 V at 25 C when the [Zn2+] = 1.0M and PH2 = 1 atm, what is the pH of the cathode solution? Zn(s)|Zn2+(aq)|| H+(aq)|H2 (g)|Pt
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If the potential of a Zn-H+ cell (see below) is 0.45 V at 25 C when...
The voltage of the following cell at 25 ̊C is + 0.65V. The standard reduction potential for Zn is -0.76 V. Zn | Zn2+ (0.60M) || H+ (aq.), H2 (g,1.0 atm) | Pt What is the pH of the solution at the cathode?
Consider a voltaic cell al 25 degree Celsius in which the reaction is: Zn (s) + 2H+ (aq) → Zn2+ (aq) + H2(g) It is found that the voltage (think Ecell) is +0.560 V when [Zn2+1 -0.85 M and PH2 = = 0.988 atm. What is the pH in the H2-H half-cell?
If the voltage of a Zn-H+ cell is 0.45 V at 25 C, when [Zn^2+] = 2.0 M and PH2 = 1 atm, calculate the concentration of H+. If the voltage of a Zn-H' cell is 0.45 V at 25°C when [Zn?) - 2.0 M and P -1.0 atm, calculate the concentration of H'.
If the voltage of a Zn-H cell is 0.45 V at 25°C when [Znat) = 2.0 M and PH2 = 1.0 atm, calculate the concentration of H". 1 = Fil 1 702
The cell potential of the following electrochemical cell depends on the gold concentration in the cathode half-cell: Pt(s)|H2(g,1atm)|H+(aq,1.0M)||Au3+(aq,?M)|Au(s). What is the concentration of Au3+ in the solution if Ecell is 1.26 V ? To what pH should you adjust a standard hydrogen electrode to get an electrode potential of -0.117 V ? (Assume that the partial pressure of hydrogen gas remains at 1 atm.) Express your answer using two decimal places.
(2 pts.) For the following electrochemical cell at 25°C: Zn(s) | Zn2+ (aq) || H+ (aq) | Pt,H2 (g) (P=1.00 atm) calculate DG° in kJ calculate Ecell for [H+] = 0.8 M and [Zn2+] = 0.5 M calculate K at 25°C
The measured voltage in a Zn-H cell is 0.45 V at 25°C when IZn*21 is 1 M. What is the concentration of H? 0592 E-E- 1g a Q = 2 4S =E A3D EZO -15.2 loj Q CH log of 3-15.2 T O.Ho cell potential, E H+] S.7X10M E.C. pH= -2
Question 1 1 pts For the cell: Zn(s) + 2H+ (aq) + Zn2+(aq) + H2 (g) If [Zn2+) = 1 M, PH2 = 1 atm, and E = 0.549 V what is pH? Question 2 1 pts Calculate the voltage for the following cell at 25° ZnZn+2 ( 2.832 M) || Cd2+ (0.027 M)| Cd
8) An electrochemical cell consists of a Pt|H+(aq,1.00 M)|H2(g) cathode connected to a Pt|H+(aq)|H2(g) anode in which the H+concentration is that of a buffer consisting of a weak acid, HA(0.115 M), mixed with its conjugate base, A-(0.192 M). The measured cell voltage is E°cell = 0.168 V at 25 °C, with PH2 = 1.00 atm at both electrodes. Calculate the pH in the buffer solution and the Ka of the weak acid. pH = Ka =
A voltaic cell consists of a Zn/Zn2+ half-cell and a Ni/Ni2+ half-cell at 25 ∘C. The initial concentrations of Ni2+ and Zn2+ are 1.60molL−1 and 0.130 molL−1, respectively. Zn2+(aq)+2e−→Zn(s)E∘=−0.76V Ni2+(aq)+2e−→Ni(s)E∘=−0.23V Part A What is the initial cell potential? Part B What is the cell potential when the concentration of Ni2+ has fallen to 0.600 molL−1? Part C What are the concentrations of Ni2+ and Zn2+ when the cell potential falls to 0.45 V?