A square current loop 5.2 cm on each side carries a 470 mA current. The loop is in a 1.3 T uniform magnetic field. The axis of the loop, perpendicular to the plane of the loop, is 30∘ away from the field direction.
What is the magnitude of the torque on the current loop?
Torque on the loop = I*A*B*sin theta
= 0.470*5.2e-2^2*1.3*sin 30 degree
= 0.000826 Nm answer
A square current loop 5.2 cm on each side carries a 470 mA current. The loop...
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