A random sample of 60 business students required an average of 50.7 minutes to complete a...
random sample of 28 students at the university showed an average age of 25 years and a sample standard deviation of 2 years. Calculate the margin of error for a confidence interval for age at the 98% level of confidence O 1.235 O : 1.645 ○ :0.945 O 0.888
A random sample of 225 exams score drawn from a large population of students has a mean of 60 and a sample standard deviation of 9. Estimate the population mean with a confidence level of 95%. _______< mean<________ Estimate the population mean with a confidence level of 98%. _______ <mean <________ Your final answers should be correct to 4 places after the decimal point. For a confidence level of 95% assuming the same statistics find the sample size that would...
Based on a random sample of 30 business students, it was found that 95% confidence interval for the average number of minutes required to complete a statistics exam is given by (40.3, 46.5). What is the point estimate for this confidence interval? (select one) 6.2 3.1 43.4 86.8
In a random sample of 8 people, the mean commute time to work was 33.5 minutes and the standard deviation was 7.4 minutes. A 98% confidence interval using thet-distribution was calculated to be (25.7,41.3). After researching commute times to work, it was found that the population standard deviation is 8.6 minutes. Find the margin of error and construct a 98% confidence interval using the standard normal distribution with the appropriate calculations for a standard deviation that is known. Compare the...
In a random sample of 25 people, the mean commute time to work was 32.9 minutes and the standard deviation was 7.1 minutes. Assume the population is normally distributed and use a t-distribution to construct a 98% confidence interval for the population mean μ: What is the margin of error of μ? Interpret the results. The confidence interval for the population mean μ is _______ The margin of error of μ is _______ Interpret the results A. If a large sample of people are...
In a random sample of 26 people, the mean commute time to work was 34.8 minutes and the standard deviation was 7.3 minutes. Assume the population is normally distributed and use a t-distribution to construct a 98% confidence interval for the population mean μ. What is the margin of error of μ? Interpret the results. The confidence interval for the population mean μ is _______ . (Round to one decimal place as needed.) The margin of error of μ is _______ (Round to...
1. A random sample of 82 customers, who visited a department store, spent an average of $71 at this store. Suppose the standard deviation of expenditures at this store is O = $19. What is the e 98% confidence interval for the population mean? 2. A sample of 25 elements produced a mean of 123.4 and a standard deviation of 18.32 Assuming that the population has a normal distribution, what is the 90% confidence interval for the population mean? 3....
In a random sample of 8 people, the mean commute time to work was 36.5 minutes and the standard deviation was 7.3 minutes. A 98% confidence interval using the t-distribution was calculated to be left parenthesis 28.8 comma 44.2 right parenthesis. After researching commute times to work, it was found that the population standard deviation is 8.5 minutes. Find the margin of error and construct a 98% confidence interval using the standard normal distribution with the appropriate calculations for a...
In a random sample of 8 people, the mean commute time to work was 36.5 minutes and the standard deviation was 7.3 minutes. A 98% confidence interval using the t-distribution was calculated to be left parenthesis 28.8 comma 44.2 right parenthesis. After researching commute times to work, it was found that the population standard deviation is 8.5 minutes. Find the margin of error and construct a 98% confidence interval using the standard normal distribution with the appropriate calculations for a...
5. The servicing time at the drive-through lane of a fast food restaurant follows an exponential distribution. The average servicing time is 2 minutes. (4 points) YORKVILLE BUSI 1013 statistics for Business What is the probability that it takes more than 2.5 minutes to service a customer at the drive-through lane? b. a. What percent of customers at the drive-through lane will take between 1 to 3 minutes to service? Part B 1. A simple random sample of 50 customers...