Question

Activity U cannot begin until both activities S and T have been completed. Activity V cannot begin until both activities S and T have been completed. The duration for U, V, and T are 53,50,37, and 31 days, Respectively. if the earliest finish time for S is at the end of day 108 and the earliest start time for T is at the end of day 77, the earliest finish time for V is at the end of day______?

Answer 1

The given information along with the dependency is captured in the network diagram below

We know that earliest finish time of the activity is given by adding the duration of the activity to its earliest start time. Also, the earliest start time of any successor activities is the higher of the earliest finish time of all the predecessor activities.

As we need to find earliest finish time of activity V, we need to find the earliest finish time of its predecessor activities S and T. The earliest finish time of activity S is given as 108. The earliest finish time of activity T is the sum of earliest start time of T which is 77 and duration of T which is 31. Hence earliest finish time of T is 77+31 = 108.

The earliest start time of activity V is than higher of earliest finish time of activity S and T. In this case both these activities have the same earliest finish time which 108. Hence the earliest start time of activity V is 108. Hence earliest finish time of activity V is the addition of 108 and it duration. Hence earliest finish time of activity V is 108+50 = 158 days.

Hence the earliest finish time of activity V is 158 days.