lm(formula = lnwage ~ female + exper + exper.sq + (female * exper) + ## (female * exper.sq) + education + married, data = df) ## Coefficients: ## Estimate Std. Error t value Pr(>|t|) ## (Intercept) 0.8032332 0.0200735 40.01 < 2e-16 *** ## female -0.0542592 0.0210303 -2.58 0.0099 ** dummy => female=1 male=0 ## exper 0.0456059 0.0014216 32.08 < 2e-16 *** ## exper.sq -0.0007692 0.0000301 -25.53 < 2e-16 *** ## education 0.1156786 0.0010345 111.82 < 2e-16 *** ## married 0.1342694 0.0074061 18.13 < 2e-16 *** dummy => married=1 otherwise=0 ## female:exper -0.0178926 0.0021015 -8.51 < 2e-16 *** ## female:exper.sq 0.0003147 0.0000461 6.83 0.0000000000086 *** (a) At what year of experience does men's return to experience start to become negative?
(b) At what year of experience does women's return to experience start to become negative?
(c) What is the earnings gap (difference in log wages between men and women) at 5 years of experience?
The regression equation is:
log(wage) = 0.803 - 0.054 * Female + 0.046 * exper - 0.0008 * exper2 + 0.116 * education + 0.134 * married - 0.0179 * female * exper + 0.0003 * female * exper2
a) For men, Female = 0
log(wage) = 0.803 - 0.054 * Female + 0.046 * exper - 0.0008 * exper2 + 0.116 * education + 0.134 * married
The men's return to experience will be positive at first and
then grab a maximum value and go negative.
Return = 0.046 * exper - 0.0008 * exper2
dR/de = 0.046 - 2*0.0008*exper = 0
exper = 0.046/0.0016 = 28.75
Hence, At 29 years of experience the men's return to experience starts to become negative
b) For a women, female = 1
log(wage) = 0.803 - 0.054 * Female + 0.046 * exper - 0.0008 * exper2 + 0.116 * education + 0.134 * married - 0.0179 * exper + 0.0003 * exper2
log(wage) = 0.803 - 0.054 * Female + 0.0281 * exper - 0.0011 * exper2 + 0.116 * education + 0.134 * married
Return = 0.0281 * exper - 0.0011 * exper2
dR/dE = 0.0281 - 0.0011*2*exper = 0
exper = 0.0281/0.0022 = 12.78
Hence, at 13 years of experience the women's return to experience starts to become negative.
c) At exper = 5
log(wage) = 0.803 - 0.054 * Female + 0.046 * 5 - 0.0008 * 25 + 0.116 * education + 0.134 * married - 0.0179 * female * 5 + 0.0003 * female * 25
log(wage) = 0.803 + 0.046*5 - 0.0008*25 + Female*(-0.054 - 0.0179*5 + 0.0003*25) + 0.116*education + 0.132*married
log(wage) = 1.013 - Female*0.136 + 0.016*education + 0.132*married
Hence, earnings gap (difference in log wages between men and women) at 5 years of experience is the coefficient of Female which is 0.136
lm(formula = lnwage ~ female + exper + exper.sq + (female * exper) + ## (female...
8. A regression of wage (log(wage) is run on a set of following variables: female (-1 if female), educ (years of education), exper (years of experience) and tenure (years with current employer). The regression results are listed as follows. Coefficients: Estimate Std. Error tvalue Pr(Itl) (Intercept) -1.56794 0.72455 -2.164 0.0309 female -1.81085 0.26483 -6.838 2.26e-11*** educ 0.57150 0.04934 11.584 <2e-16*** 0.02540 0.01157 2.195 0.0286 exper 0.14101 0.02116 6.663 6.83e-11*** tenure Signif. codes:0.0010.010.050.1'"1 Residual standard error: 2.958 on 521 degrees of...
8. A regression of wage (log(wage) is run on a set of following variables: female (-1 if female), educ (years of education), exper (years of experience) and tenure (years with current employer). The regression results are listed as follows. Coefficients: Estimate Std. Error tvalue Pr(Itl) (Intercept) -1.56794 0.72455 -2.164 0.0309 female -1.81085 0.26483 -6.838 2.26e-11*** educ 0.57150 0.04934 11.584 <2e-16*** 0.02540 0.01157 2.195 0.0286 exper 0.14101 0.02116 6.663 6.83e-11*** tenure Signif. codes:0.0010.010.050.1'"1 Residual standard error: 2.958 on 521 degrees of...
8. A regression of wage (log(wage) is run on a set of following variables: female (-1 if female), educ (years of education), exper (years of experience) and tenure (years with current employer). The regression results are listed as follows. Coefficients: Estimate Std. Error tvalue Pr(Itl) (Intercept) -1.56794 0.72455 -2.164 0.0309 female -1.81085 0.26483 -6.838 2.26e-11*** educ 0.57150 0.04934 11.584 <2e-16*** 0.02540 0.01157 2.195 0.0286 exper 0.14101 0.02116 6.663 6.83e-11*** tenure Signif. codes:0.0010.010.050.1'"1 Residual standard error: 2.958 on 521 degrees of...
Using the book, write another paragraph or two: write 170 words: Q: Compare the assumptions of physician-centered and collaborative communication. How is the caregiver’s role different in each model? How is the patient’s role different? Answer: Physical-centered communication involves the specialists taking control of the conversation. They decide on the topics of discussion and when to end the process. The patient responds to the issues raised by the caregiver and acts accordingly. On the other hand, Collaborative communication involves a...