Please help
calculate kab for the reaction A2-+B3- --> A3- + B2-
for self exchange of A Eo=0.68V and kaa =7.4x102
for self exchange of B E0=0.54V and kbb=7x104
E0cell=Eocathode-EoAnode
K12=e-(-nFEcell/RT) F=96500
use marcus relationship kab=(kabkbbKab)1/2
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Please help calculate kab for the reaction A2-+B3- --> A3- + B2- for self exchange of...
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