Question

If 4.0×10⁻⁴ moles of S2O2−8 in 200 mL of solution is consumed in 190 seconds , what is the rate of consumption of S2O2−8?

Answer 1

Number of moles of =4.0x10^-4 mol

Volume of solution=200 mL=200 mL/1000 mL/L=0.2 L (1 L=1000 mL)

Concentration of =[]=number of moles of /Volume of solution (L)

=4.0x10^-4 mol/0.2 L=2.0 x 10^-3 mol/L

Time taken to consume in given solution=190 s

Rate of consumption of =Concentration of consumed/Time taken=(2.0 x 10^-3 mol/L)/190 s=0.11 x 10^-4 mol L^{​​​​-1} s^{​​​​​​-1}