The research team would like to estimate the average gender difference in age.
Compute a 90% estimate and confidence interval for the difference in the average age of Female and Male employees.
What is the margin of error of the confidence interval ? (Use 3 decimals)
Employee Number1 | Annual Salary | Gender | Age (years) | Experience (years) | Training Level |
1 | $ 32,368 | F | 42 | 3 | B |
2 | $ 53,174 | M | 54 | 10 | B |
3 | $ 52,722 | M | 47 | 10 | A |
4 | $ 53,423 | M | 47 | 1 | B |
5 | $ 50,602 | M | 44 | 5 | B |
6 | $ 49,033 | M | 42 | 10 | A |
7 | $ 24,395 | M | 30 | 5 | A |
8 | $ 24,395 | F | 52 | 6 | A |
9 | $ 43,124 | M | 48 | 8 | A |
10 | $ 23,975 | F | 58 | 4 | A |
11 | $ 53,174 | M | 46 | 4 | C |
12 | $ 58,515 | M | 36 | 8 | C |
13 | $ 56,294 | M | 49 | 10 | B |
14 | $ 49,033 | F | 55 | 10 | B |
15 | $ 44,884 | M | 41 | 1 | A |
16 | $ 53,429 | F | 52 | 5 | B |
17 | $ 46,574 | M | 57 | 8 | A |
18 | $ 58,968 | F | 61 | 10 | B |
19 | $ 53,174 | M | 50 | 5 | A |
20 | $ 53,627 | M | 47 | 10 | B |
21 | $ 49,033 | M | 54 | 5 | B |
22 | $ 54,981 | M | 47 | 7 | A |
23 | $ 62,530 | M | 50 | 10 | B |
24 | $ 27,525 | F | 38 | 3 | A |
25 | $ 24,395 | M | 31 | 5 | A |
26 | $ 56,884 | M | 47 | 10 | A |
27 | $ 52,111 | M | 56 | 5 | A |
28 | $ 44,183 | F | 38 | 5 | B |
29 | $ 24,967 | F | 55 | 6 | A |
30 | $ 35,423 | F | 47 | 4 | A |
31 | $ 41,188 | F | 35 | 2 | B |
32 | $ 27,525 | F | 35 | 3 | A |
33 | $ 35,018 | M | 39 | 1 | A |
34 | $ 44,183 | M | 41 | 2 | A |
35 | $ 35,423 | M | 44 | 1 | A |
36 | $ 49,033 | M | 53 | 8 | A |
37 | $ 40,741 | M | 47 | 2 | A |
38 | $ 49,033 | M | 42 | 10 | A |
39 | $ 56,294 | F | 44 | 6 | C |
40 | $ 47,180 | F | 45 | 5 | C |
41 | $ 46,574 | M | 56 | 8 | A |
42 | $ 52,722 | M | 38 | 8 | C |
43 | $ 51,237 | M | 58 | 2 | B |
44 | $ 53,627 | M | 52 | 8 | A |
45 | $ 53,174 | M | 54 | 10 | A |
46 | $ 56,294 | M | 49 | 10 | B |
47 | $ 49,033 | F | 53 | 10 | B |
48 | $ 49,033 | M | 43 | 9 | A |
49 | $ 55,549 | M | 35 | 8 | C |
50 | $ 51,237 | M | 56 | 1 | C |
51 | $ 35,200 | F | 38 | 1 | B |
52 | $ 50,175 | F | 42 | 5 | A |
53 | $ 24,352 | F | 35 | 1 | A |
54 | $ 27,525 | F | 40 | 3 | A |
55 | $ 29,606 | F | 34 | 4 | B |
56 | $ 24,352 | F | 35 | 1 | A |
57 | $ 47,180 | F | 45 | 5 | B |
58 | $ 49,033 | M | 54 | 10 | A |
59 | $ 53,174 | M | 47 | 10 | A |
60 | $ 53,429 | F | 45 | 7 | B |
61 | $ 53,627 | M | 47 | 10 | A |
62 | $ 26,491 | F | 46 | 7 | A |
63 | $ 42,961 | M | 36 | 3 | B |
64 | $ 53,174 | M | 45 | 5 | A |
65 | $ 36,292 | M | 46 | 0 | A |
66 | $ 37,292 | M | 47 | 1 | A |
67 | $ 41,188 | F | 34 | 3 | B |
68 | $ 57,242 | F | 45 | 7 | C |
69 | $ 53,429 | F | 44 | 6 | C |
70 | $ 53,174 | M | 50 | 10 | B |
71 | $ 44,138 | F | 38 | 2 | B |
F | M | |
42 | 54 | |
52 | 47 | |
58 | 47 | |
55 | 44 | |
52 | 42 | |
61 | 30 | |
38 | 48 | |
38 | 46 | |
55 | 36 | |
47 | 49 | |
35 | 41 | |
35 | 57 | |
44 | 50 | |
45 | 47 | |
53 | 54 | |
38 | 47 | |
42 | 50 | |
35 | 31 | |
40 | 47 | |
34 | 56 | |
35 | 39 | |
45 | 41 | |
45 | 44 | |
46 | 53 | |
34 | 47 | |
45 | 42 | |
44 | 56 | |
38 | 38 | |
58 | ||
52 | ||
54 | ||
49 | ||
43 | ||
35 | ||
56 | ||
54 | ||
47 | ||
47 | ||
36 | ||
45 | ||
46 | ||
47 | ||
50 | ||
mean | 43.96429 | 46.55814 |
sd | 7.805421 | 6.877508 |
n | 28 | 43 |
M1 & M2 = sample
means
t = t statistic determined by confidence
level
s(M1 - M2) = standard
error =
√((s2p/n1)
+
(s2p/n2))
μ1 - μ2 = (M1 - M2) ± ts(M1 - M2)
margin or error = ts(M1 - M2)
Calculation
Pooled
Variance
s2p =
((df1)(s21) +
(df2)(s22)) /
(df1 + df2) = 3631.57 / 69
= 52.63
Standard
Error
s(M1 - M2) =
√((s2p/n1)
+
(s2p/n2))
= √((52.63/28) + (52.63/43)) = 1.76
Margin of error
= 1.67 * 1.76 = 2.9392
Confidence
Interval
μ1 - μ2 = (M1 -
M2) ±
ts(M1 -
M2) = 2.5939 ± (1.67 * 1.76) = 2.5939 ±
2.9372187
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