SOLUTION :
Let X is a random variable shows the winning amount. Here X can take values $5, $4, $3 and $0.
When a single fair die is rolled the possible outcomes are 1, 2, 3, 4, 5, and 6.
Out of 6 outcomes, 1 is 6 so when X= $5 then
P(X=$5) = 1/6
Out of 6 outcomes, 1 is 5 so when X= $4 then
P(X=$4) = 1/6
Out of 6 outcomes, 1 is 4 so when X= $3 then
P(X=$3) = 1/6
And
P(X=$0) = 1- P(X=$5) - P(X=$4) - P(X=$3) = 3/6
Following table shows calculations for expected winning:
X | P(X=x) | xP(X=x) |
5 | 1/6 | 5/6 |
4 | 1/6 | 4/6 |
3 | 1/6 | 3/6 |
0 | 3/6 | 0 |
Total | 2 |
So expected winning is
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