here,
theta = 35 degree
let the radius of the path be R
the speed of plane , v = 2 *pi * R /T
v = 2*pi*r /15 ....(1)
equating the forces vertically
N * cos(theta) = m * g ....(1)
and
N * sin(theta) = m * v^2 /r .....(2)
from (1) and (2)
tan(theta) = v^2 /(rg)
tan(45) = (2*pi*r/15 )^2 /(r * 9.81 )
solving for r
r = 55.9 m
the radius of track is 55.9 m
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