For the cell Pt(s)│VO2+ (0.116M), V3+ (0.116M), H+ (1.57 M) ││ Sn2+ (0.0318 M), Sn4+ (0.0318...
For the cell Pt(s)│VO2+ (0.116M), V3+ (0.116M), H+ (1.57 M) ││ Sn2+ (0.0318 M), Sn4+ (0.0318 M) │Pt (s)
If the Ecell = ‒ 0.289 V then calculate the equilibrium constant. Is the reaction spontaneous as written? Explain why.
Hint: Use the ion-electron method to determine the power of [H+] in the Nernst equation.
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For the cell Pt(s)│VO2+ (0.116M), V3+ (0.116M), H+ (1.57 M) ││
Sn2+ (0.0318 M), Sn4+ (0.0318...
Calculate the potential of the electrochemical cell and determine if it is spontaneous as written at 25 °C Cu(s) Cu2 (0...
Calculate the potential of the electrochemical cell and determine if it is spontaneous as written at 25 °C Cu(s) Cu2 (0.12 M |Fe2 (0.0012 M) Fe(s) E2 =-0.440 V Efe/Fe = 0.339 V Cu2t/Cu Is the electrochemical cell spontaneous or not spontaneous Ecell V as written at 25 °C? not spontaneous spontaneous Calculate the potential of the electrochemical cell and determine if it is spontaneous as written at 25 °C. Pt(s) Sn2(0.0060 M), Sn4+(0.14 M) Fe3+(0.13 M), Fe2+(0.0056 M) Pt(s)...
which of the following spontaneous reactions is associated with the cell, Pt(s)l Sn2+,Sn4+ll Ag+ l Ag(s)...
which of the following spontaneous reactions is associated with the cell, Pt(s)l Sn2+,Sn4+ll Ag+ l Ag(s) a)Aq + e---> Ag+ c)Pt + 2e- --> Pt2- d)sn4+ + Ag+ --> Pt2+ Ag(s) + Sn2+ e) none of the above
Calculate the potential of the electrochemical cell and determine if it is spontaneous as written at...
Calculate the potential of the electrochemical cell and determine if it is spontaneous as written at 25 °C Cu(s) Cu2+ (0.15 M) Fe2+ (0.0039 M) Fe(s) E =-0.440 V E+Cu = 0.339 V Fe2+/Fe Is the electrochemical cell spontaneous or not spontaneous -0.779 Ecell = as written at 25 C? not spontaneous spontaneous о Calculate the potential of the electrochemical cell and determine if it is spontaneous as written at 25 'C Pt(s) Sn2 (0.0024 M), Sn4+ (0.12 M) |...
A concentration cell is set up using the following reaction: Sn4+ (aq) + 2e – Sn2+...
A concentration cell is set up using the following reaction: Sn4+ (aq) + 2e – Sn2+ (aq) ° = 0.150 V The standard line notation, including initial concentrations, for this cell is shown below: (Please note that concentration of ions shown in the anode compartment are in the same order as in the cathode compartment.) Pt (s)[Sn4+] (0.645 M), [Sn2+ ](1.39 M) || (Sn4+] (1.37 M), [Sn2+] (0.611 M) |Pt (s) The initial potential of this concentration cell, at 298...
For the electrochemical cell Pt(s) | Sn2+(aq), Sn4+(aq) || Pb2+(aq) | Pb(s), what is the function...
For the electrochemical cell Pt(s) | Sn2+(aq), Sn4+(aq) || Pb2+(aq) | Pb(s), what is the function of the Pt(s)? Pt is the anode and is a reactant in the overall cell reaction. Pt is the anode and does not appear in the overall cell reaction. Pt is the cathode and is a product in the overall cell reaction. O Pt is the cathode and does not appear in the overall cell reaction. O
Calculate the potential of the electrochemical cell and determine if it is spontaneous as written at...
Calculate the potential of the electrochemical cell and determine if it is spontaneous as written at 25 °C. Cu(s) Cu2+(0.14 M) | Fe2+(0.0044 M) Fe(s) Ecu?+Icu = 0.339 V Efez lfe = -0.440 V Ecell = v Is the electrochemical cell spontaneous or not spontaneous as written at 25 °C? O not spontaneous O spontaneous Calculate the potential of the electrochemical cell and determine if it is spontaneous as written at 25 °C. Pt(s) Sn2+(0.0048 M), Snº+(0.11 M) || Fe3+(0.12...
Conceptual: Consider a Sn(s)|Sn2+(aq) || Cu2+(aq)|Cu(s) cell. If the Sn2+ concentration is increased, what will happen...
Conceptual: Consider a Sn(s)|Sn2+(aq) || Cu2+(aq)|Cu(s) cell. If the Sn2+ concentration is increased, what will happen to the measured Ecell value? • Calculation, full-reaction Nernst equation: Use the full Nernst equation to calculate Ecell for the conditions described… • Easier: Ni | Ni2+(0.300 M) || Cu2+(0.002 M) | Cu • Harder: Al | Al3+(0.002 M) || Cu2+(4.00 M) | Cu • Calculation, half-reaction Nernst equation: Use the Nernst equation to calculate E at pH 3.00 and [Cl- ] = 0.0035...
Half-reaction Cr3+ (aq) + 3e- → Cr(s) Fe2+ (aq) + 2e- → Fe (s) Fe3+ (aq) + e- + Fe2+ (s) Sn4+ (aq) + 2e- + Sn2+ (aq...
Half-reaction Cr3+ (aq) + 3e- → Cr(s) Fe2+ (aq) + 2e- → Fe (s) Fe3+ (aq) + e- + Fe2+ (s) Sn4+ (aq) + 2e- + Sn2+ (aq) E° (V) -0.74 -0.440 +0.771 +0.154 3Sn** (aq) +2Cr(s) → 2Cr** (aq) +3Sn²+ (aq) 3. What is the cell potential, Ecell, for the reaction above if [Sn] = 1.00 M, [Cr3+1 = 0.0200 M and [Sn2+] = 0.0100 M?
Мар You are performing a titration of 25.0 mL of 0.0100 M Sn4 in 1 M HCI with 0.0500 M Ag* to give Sn2 anu 3+ Ags using...
Мар You are performing a titration of 25.0 mL of 0.0100 M Sn4 in 1 M HCI with 0.0500 M Ag* to give Sn2 anu 3+ Ags using a Pt indicator electrode and a saturated calomel electrode (SCE) as the reference electrode. A) Write the balanced titration reaction B) Complete the two half-reactions that occur at the indicator electrode (shown is their corresponding reduction potential) Sn E 0.139 V 3+ Ag® Eo 1.90 V C) Choose the two different expressions...
Consider the galvanic cell described by (N and M are metals): N(s)|N2+(aq)||M+(aq)|M(s) If Eocathode = 0.585...
Consider the galvanic cell described by (N and M are
metals):
N(s)|N2+(aq)||M+(aq)|M(s)
If Eocathode = 0.585 V and
Eoanode = 1.27 V, and
[N2+(aq)] = 0.22 M and [M+(aq)] = 0.475 M,
what is Ecell, using the Nernst equation? ____
V
Provide your response to two digits after the decimal.
Question 1 1 pts Consider the galvanic cell described by (N and Mare metals): N(s)|N2+(aq)||M+(aq)|M(s) If Eºcathode = 0.585 V and Eanode = 1.27 V, and [N2+(aq)] = 0.22 M...
Calculate the potential of the electrochemical cell and determine if it is spontaneous as written at 25 °C Cu(s) Cu2 (0.12 M |Fe2 (0.0012 M) Fe(s) E2 =-0.440 V Efe/Fe = 0.339 V Cu2t/Cu Is the electrochemical cell spontaneous or not spontaneous Ecell V as written at 25 °C? not spontaneous spontaneous Calculate the potential of the electrochemical cell and determine if it is spontaneous as written at 25 °C. Pt(s) Sn2(0.0060 M), Sn4+(0.14 M) Fe3+(0.13 M), Fe2+(0.0056 M) Pt(s)...
Calculate the potential of the electrochemical cell and determine if it is spontaneous as written at 25 °C Cu(s) Cu2+ (0.15 M) Fe2+ (0.0039 M) Fe(s) E =-0.440 V E+Cu = 0.339 V Fe2+/Fe Is the electrochemical cell spontaneous or not spontaneous -0.779 Ecell = as written at 25 C? not spontaneous spontaneous о Calculate the potential of the electrochemical cell and determine if it is spontaneous as written at 25 'C Pt(s) Sn2 (0.0024 M), Sn4+ (0.12 M) |...
A concentration cell is set up using the following reaction: Sn4+ (aq) + 2e – Sn2+ (aq) ° = 0.150 V The standard line notation, including initial concentrations, for this cell is shown below: (Please note that concentration of ions shown in the anode compartment are in the same order as in the cathode compartment.) Pt (s)[Sn4+] (0.645 M), [Sn2+ ](1.39 M) || (Sn4+] (1.37 M), [Sn2+] (0.611 M) |Pt (s) The initial potential of this concentration cell, at 298...
For the electrochemical cell Pt(s) | Sn2+(aq), Sn4+(aq) || Pb2+(aq) | Pb(s), what is the function of the Pt(s)? Pt is the anode and is a reactant in the overall cell reaction. Pt is the anode and does not appear in the overall cell reaction. Pt is the cathode and is a product in the overall cell reaction. O Pt is the cathode and does not appear in the overall cell reaction. O
Calculate the potential of the electrochemical cell and determine if it is spontaneous as written at 25 °C. Cu(s) Cu2+(0.14 M) | Fe2+(0.0044 M) Fe(s) Ecu?+Icu = 0.339 V Efez lfe = -0.440 V Ecell = v Is the electrochemical cell spontaneous or not spontaneous as written at 25 °C? O not spontaneous O spontaneous Calculate the potential of the electrochemical cell and determine if it is spontaneous as written at 25 °C. Pt(s) Sn2+(0.0048 M), Snº+(0.11 M) || Fe3+(0.12...
Half-reaction Cr3+ (aq) + 3e- → Cr(s) Fe2+ (aq) + 2e- → Fe (s) Fe3+ (aq) + e- + Fe2+ (s) Sn4+ (aq) + 2e- + Sn2+ (aq) E° (V) -0.74 -0.440 +0.771 +0.154 3Sn** (aq) +2Cr(s) → 2Cr** (aq) +3Sn²+ (aq) 3. What is the cell potential, Ecell, for the reaction above if [Sn] = 1.00 M, [Cr3+1 = 0.0200 M and [Sn2+] = 0.0100 M?
Мар You are performing a titration of 25.0 mL of 0.0100 M Sn4 in 1 M HCI with 0.0500 M Ag* to give Sn2 anu 3+ Ags using a Pt indicator electrode and a saturated calomel electrode (SCE) as the reference electrode. A) Write the balanced titration reaction B) Complete the two half-reactions that occur at the indicator electrode (shown is their corresponding reduction potential) Sn E 0.139 V 3+ Ag® Eo 1.90 V C) Choose the two different expressions...
Consider the galvanic cell described by (N and M are
metals):
N(s)|N2+(aq)||M+(aq)|M(s)
If Eocathode = 0.585 V and
Eoanode = 1.27 V, and
[N2+(aq)] = 0.22 M and [M+(aq)] = 0.475 M,
what is Ecell, using the Nernst equation? ____
V
Provide your response to two digits after the decimal.
Question 1 1 pts Consider the galvanic cell described by (N and Mare metals): N(s)|N2+(aq)||M+(aq)|M(s) If Eºcathode = 0.585 V and Eanode = 1.27 V, and [N2+(aq)] = 0.22 M...
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