Fusion problems, find the energy release
Solution:
a) 2H +3H → 4He + 1n
E =
mc2
= [4.00260 + 1.007825- 3.01605 - 2.014102 ]*931.5
= - 18.4 MeV
b) 4He +4He → 7Be + 1n
E =
mc2
= [7.01692872 + 1.007825- 2*4.00260 ]*931.5
= 18.2 MeV .
c) 2H +3He → 4He + 1n
E =
mc2
= [4.00260 + 1.007825- 3.01605 - 2.014102 ]*931.5
= -18.4 MeV .
d) 2H + 1H → ᵞ+ 3H
E =
mc2
= [3.01605 - 2.014102 - 1.007825]*931.5
= -5.5 MeV.
I hope you understood the problem and got your answers, If yes rate me!! or else comment for a better solutions
Fusion problems, find the energy release 2H +3H → 4He + ? 4He +4He → 7Be...
Complete the following fusion process: 1H+2H⟶−−−−−− Complete the following fusion process: 31n 4He 3He 1n
Find the energy Q released in the fusion reaction. (Note that the reaction below is between nuclei. For the atomic masses, see this table. The mass of an electron is 0.00054 1H+3He → 4He + e+ + ν MeV
Find the energy Q released in the fusion reaction. (Note that the reaction below is between nuclei. For the atomic masses, see this table. The mass of an electron is 0.00054 1H+3He → 4He + e+ + ν MeV
4He is formed when isotopes of hydrogen undergo fusion. What is the energy associated with the formation of 2.00 g of 4He (1 mole = 4.00260 g) by the fusion of 3H and 1H? ΔE for the formation of one atom of 4He is -3.17603×10-12 J.
Complete the following fusion reaction: 4He+3He⟶2H+−−−−−−. Express your answer as a complete nuclear equation. nothing SubmitRequest Answer
How much energy (in MeV) is released during the following fusion reaction? 1H + 2H → 3He Molar mass of 1H = 1.00728 g/mol Molar mass of 2H = 2.01355 g/mol Molar mass of 3He = 3.01493 g/mol 1 MeV = 1.60218 * 10-13 J
How much energy (in MeV) is released during the following fusion reaction? 1H + 2H → 3He Molar mass of 1H = 1.00728 g/mol Molar mass of 2H = 2.01355 g/mol Molar mass of 3He = 3.01493 g/mol 1 MeV = 1.60218 * 10-13 J Report your answer to one decimal place. Do not input a unit or a sign (+/-).
Using the table below, find the Q values for the following
reactions.
(a) n + 3He --> 3H + 1H + Q MeV
(b) n + 6Li --> 3H + 4He + Q MeV
(c) 7Li + 1H --> 4He + 4He + Q MeV
Consider the proton–proton cycle that occurs in most stars (including our own Sun): Step 1: 1H + 1H → 2H + e+ + νe Step 2: 2H + 1H → 3He + γ Step 3: 3He + 3He → 4He + 2 1H + γ Calculate the net energy released from the three steps. Do not ignore the mass of the positron in Step 1. (You may ignore the mass of the neutrino.) MeV
Determine the structural formula for each
8 PPM c. CSH10O2 =0 3H 3H 2H 2H 5 PPM CSH1002 d. 3H 3H 3H 1H PPM 45)
Calculate the binding energy per nucleon (in J) for 3He and 4He. The atomic masses are 3.016029 u for 3He, and 4.002603 u for 4He. (Enter unrounded values. Assume that the mass of 11H = 1.007825 u, mp = 1.007275 u, mn = 1.008666 u, and me = 0.000549 u, respectively.)