What is the pH of a 0.052 M solution of Sodium acetate? Ka = 1.8 × 10^-5?
a)11.4 b)2.6 c)11.0 d)8.7) E )10.0
known that correct answer is D 8.7.
Pls explain why
What is the pH of a 0.052 M solution of Sodium acetate? Ka = 1.8 ×...
Calculate the pH of a 0.50 M solution of sodium acetate (NaCH3COO) given that the Ka of acetic acid (CH3COOH) is 1.8 x 105, A 9.26 B.9.22 11.48 D.4.78 E. 2.52
Calculate the pH of a 0.40 M solution of sodium acetate (NaCH3COO) given that the Ka of acetic acid (CH3COOH) is 1.8 x 10 5. Ο Α. 2.57 Ο Ο Β. 9.17 Ο C.9.26 Ο Ο D. 4.83 Ο Ο Ε. 11.43
Determine the pH of a 0.11 M solution of sodium acetate (CH3COONa) at 25 ° C. (Ka of acetic acid = 1.8 × 10−5.) pH =
3.) A solution of sodium acetate has a pH of 9.07. Ka (HC2H302) 1.8 x 103 What is the molarity of the solution?
Calculate the pH of a 0.575 M of sodium acetate (NaCH3COO). Ka for acetic acid is 1.8 × 10-5.
(C))3.75 moo (D) 4.75 (E) 5.75 bios nA oir 9. Ka of acetic acid is 1.8 x 10. What is the pH of a solution 0.1M acetic acid and 0.05M sodium acetate? (A) 4.44 oasd A (B) 4.74 (C) 4.96 (D) 5.04 (E) 5.56 10. A buffer solution containing 0.5M acetic acid and 0.5M sodium acetate hais a pH ot 4.745. 5ml 2M sodium hydroxide is added to 995ml of the buffer solution. What is final pH? (A) 4.569 (C))3.75...
Calculate the pH of a solution made by adding 42 g of sodium acetate, NaCH3COO, to 22 g of acetic acid, CH3COOH, and dissolving in water to make 300. mL of solution. Hint given in feedback. The K, for CH3COOH is 1.8 x 10-5 M. As usual, report pH to 2 decimal places. Answer: Calculate the pH of a solution made by adding 59 g of sodium acetate, NaCH3COO, to 22 g of acetic acid, CH3COOH, and dissolving in water...
What is the pH of a solution that is 0.785 M in acetic acid and 0.451 M is sodium acetate. The Ka for acetic acid is 1.8 x 10-5 . A. 4.74 B. 4.50 C. 4.74 D. 4.98 E. 5.50
what is the pH of this solution: adding 1.64 grams of sodium acetate to give 200.0 mL solution at 25 degrees celsius. the Ka for acetic acid is 1.8 x 10^-5
Calculate the pH of a 0.0107 M sodium formate solution. Ka (HCHO2) = 1.8 × 10−4. Report your answer to TWO places past the decimal.