In the game of roulette, a player can place a
$10bet on the number 25and have a 1/38probability of winning. If the metal ball lands on
25, the player gets to keep the $10
paid to play the game and the player is awarded an additional
$350.Otherwise, the player is awarded nothing and the casino takes the player's
$10.
Find the expected value E(x) to the player for one play of the game. If x is the gain to a player in a game of chance, then E(x) is usually negative. This value gives the average amount per game the player can expect to lose.
TOPIC:Expected gain of the game of chance.
Hence,The expected gain= - $0.5263.
So,the player can expect to loss $0.5263,on average.(ANSWER)
In the game of roulette, a player can place a $10bet on the number 25and have...
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