You place a coin with a mass of 0.006 kg 0.0254 meters from the center of...
You place a coin with a mass of 0.006 kg 0.0254 meters from the center of the table. There is friction between the coin and the table (μs = 0.6, μk = 0.4). You turn the turntable on and it spins up slowly to 33.3rpm. Will the coin slide off?
Homework Answers
Coin will slide of the table, if static friction force on coin is lower than the centripetal force on coin.
Centripetal force on coin will by:
F = m*ac = m*w^2*r
w = 33.3 rpm = 33.3*2*pi/60 = 3.4872 rad/sec
r = 0.0254 m
So,
F = 0.006*0.0254*3.4872^2 = 0.00185 N
Now Friction force on coin will be:
Ff = us*Fn = us*m*g
Ff = 0.6*0.006*9.81
Ff = 0.035 N
Since Ff > F, So coin will not start motion, Coin will not slide off the table.
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Given: a mass (50) kg is on the edge of a rough horizontal turntable with radius...
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a mass (50) kg is on the edge of a rough horizontal turntable with radius R = 2.00 m
Friction coefficients between the mass and the table are μs = 0.50 and μk = 0.40.
The table starts to rotate (rotate) around the vertical axis of symmetry with a constant angular acceleration α = 0.60 rad / s2.
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turntable with radius R = 2.00 m Friction coefficients between the
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rotate (rotate) around the vertical axis of symmetry with a
constant angular acceleration α = 0.60 rad / s2.
It has been asked to calculate the time at which the mass just
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The table starts to rotate (rotate) around the vertical axis of symmetry with a constant angular acceleration α = 0.60 rad / s2.
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a mass (50) kg is on the edge of a rough horizontal turntable
with radius R = 2.00 m
Friction coefficients between the mass and the table are μs =
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The table starts to rotate (rotate) around the vertical axis of
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s2.
It has been asked to calculate the speed v* on which the mass
just will not shift. We must use a...
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