How much heat is required to convert 5.0 kg of ice from a temperature of -10 C to water vapor at a temperature of 213 degrees F?
T = 213 F = 100.56 C
Net heat required
Q = heat required to change temp of ice to 0
+ change the state from ice to water
+ change temp of water to 100
+ change of state from water
+ change of temp of stem to
= m ( Ci (10) + Lf + Cw (100) + Lv + Cs *100.56)
= 5* (2040*10 + 3.32* 10^5 + 4186* 100 + 2260* 10^3 + 2.01* 10^3*0.56)
= 1.52 x 10^7 J
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