An urn contains 10 white and 6 black balls. Balls are randomly selected, one at a...
An urn contains 10 white and 6 black balls. Balls are randomly selected, one at a time, until a black one is obtained. If we assume that each ball selected is replaced before the next one is drawn, what is the probability that
a) exactly 5 draws are needed?
b) at least 3 draws are needed?
Homework Answers
P(black) = 6/16 = 3/8
P(white) = 10/16 = 5/8
a) P(exactly 5 draws are needed) = P(first 4 draws white) x P(5th draw is black)
= (5/8)4 x 3/8
= 0.0572
b) P(at least 3 draws are needed) = P(first 2 draws are white)
= (5/8)2
= 0.3906
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