Question

Suppose that the efficacy of a certain drug is 0.63. Consider the sampling distribution (sample size...

Suppose that the efficacy of a certain drug is 0.63. Consider the sampling distribution (sample size n = 143) for the proportion of patients cured by this drug.

What is the mean of this distribution?

What is the standard error of this distribution?

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Answer #1

mean of the proportion = 0.63

standard error of proportion = sqrt(p*(1-p)/n)
= sqrt(0.63*(1-0.63)/143)
= 0.0404

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