Calculate the boiling point of a solution of 10.0 grams of picric acid, C6H2(OH)(NO2)3(s), dissolved in 100.0 grams of cyclohexane, C6H12(s). Assume that the colligative molality and the molality are the same for picric acid in cyclohexane.
not sure if more information is needed. this is all i got!
Calculate the boiling point of a solution of 10.0 grams of picric acid, C6H2(OH)(NO2)3(s), dissolved in...
Calculate the normal boiling point of a solution consisting of 1.0 gram of naphthalene dissolved in 100.0 grams of toluene. The normal boiling point of toluene is 110.70C and the boiling point constant is 36.1 K
9. Calculate the normal boiling point of a solution consisting of 1.0 gram of naphthalene dissolved in 100.0 grams of toluene. The normal boiling point of toluene is 110.7°C and the boiling point constant is 36.1 K. (6 pts)
When 10.0 grams of LiBr are dissolved in 100.0 grams of water in a calorimeter, the temperature increases from 30.00°C to 42.22°C. Use this information to determine the enthalpy change in units of kJ/mol of reaction. Assume the specific heat of the solution is the same as that of pure water (4.18 J/g •°C). -120. kJ -4.43 kJ -4.88 kJ -56.2 kJ -48.8 kJ
Calculate the freezing point and boiling point of a solution containing 10.0 g of naphthalene (C10Hz) in 100.0 mL of benzene. Benzene has a density of 0.877 g/cm².
Colligative properties, such as boiling point elevation, depend on the number of dissolved particles in solution. For nonelectrolytes, no dissociation occurs, and so you can use the number of moles of solute to calculate both molality and molarity. In contrast, electrolytes dissociate, and therefore the molality and molarity must be calculated based on the number of moles of dissociated particles or ions. There are two ions per formula unit of NaCl. Therefore, we would expect the freezing-point depression ΔTf of...
Need help with these both please
Two aqueous soiutions are prepared in which one contains 0.275 moles of the nonvolatile so glucose (ClO dissolved in 2500.00 g of water and the other solution contains 0.275 moles of the nonvolatile solute CaCI, dissolved in 2500.00 g of water. Describe how each of the colligative properties listed below would be affected for each of these solutions (for each olatile solut 4. is a decrease or an increase then identify which of the...
d. From the graph determine the freezing point of Pure Water: Unknown Solution: e. Calculate the freezing point depression of the solution AT f. Calculate the molality of the solution (m) g. Calculate the molar mass of the unknown. 2. What are colligative properties? List three colligative properties. 3. What effect does the presence of a nonvolatile solute have upon the boiling point of a solution? 4. What mass of glucose (CH1,.) should be dissolved in 10.00 kg of water...
An aqueous sucrose solution freezes at -0.210 degree C. Calculate the normal boiling point and the molality of an aqueous glucose solution having the same vapor pressure. Assume ideal solution behavior and kf and kb for water are 1.86 and 0.52 K-kg/mol, respectively.
REVIEW QUESTIONS 1. How many grams of ethylene glycol, C,H,(OH)2, are needed per kilogram of water to protect radiator fluid against freezing down to -15°C? For water, the freezing point constant, Kp, is 1.86°C kg mol-! CH (OH), does not dissociate in aqueous solution, i = 1. 2. For benzene, CH, the freezing point constant, K, is 5.12°C kg mol-1 and its normal freez- ing point is 5.5°C. What is the freezing point of a solution containing 100.0 g of...
(a) Calculate the ratio of dissolved benzoic acid to benzoic ion that will exist in solution at equilibrium at pH of 2.00. The acid equilibrium constant (Ka) for benzoic acid is 6.46x10^-5. Note that this calculation doesn't account for the benzoic acid that has precipitated from solution, but you can assume that the higher the ratio, the more benzoic acid will precipitate. (b) Carry out the same calculation for a pH of 4.00, and explain why it was important to...