Question

Python Programming

Task 2: Leap Years  

Part A - Is this a leap year?
Write a function is leap year(year) that calculates whether a given (CE) year is a leap year. The function must: • take one argument: a positive integer representing a year (assumed to be CE) • return True if that year was a leap year; return False if not
NOTE: all years that are divisible by four are leap years, unless they are also divisible by 100, in which case they are only leap years if they are also divisible by 400.

Part B - 2000 was a leap year.
Write a function leap year answer(year) that returns the string ‘Year was a leap year’, ‘Year was not a leap year’, ‘Year will be a leap year’, ‘Year will not be a leap year’. For the purpose of tense, you may assume 2020 and any early year are past tense; the year 2021 and onwards are future tense. You may wish to call your function from Part A as part of this function

# Task 2
def is_leap_year(year):
pass

def leap_year_answer(year):
pass

Answer 1

Dear Student,

Thanks for posting an interesting Python programming question to determine whether the argument year is a leap year or not. In the second question to print the message according to the given year and tense.

For the given year to be a leap year any of the below two conditions should be satisfied:-

i) If the year is divisible by 4 and not a century year i.e. not divisible by 100 then it is a leap year

ii) If the year is divisible by 400 i.e. century year then it is a leap year

1. For the given question, I have created and completed both the functions with proper comments. Please find below leapyear.py file contens with proper comments. Please note that both the functions are placed in a single file only and few test input cases are also provided.:-

2. Please find below the complete program in text format for ready copying with proper comments:-

def is_leap_year(year):#defining function is_leap_year

   isLeapYear=False#initializing a boolean variable isLeapYear as False in starting
   #If the year is divisible by 4 and not a century year i.e. not divisible by 100 then it is a leap year
   # or if the year is divisible by 400 i.e. century year then it is a leap year
   if (year%4==0 and year%100!=0) or year%400==0:
       isLeapYear=True;# Setting the isLeapYear as True

   return isLeapYear#Return the isLeapYear
  
def leap_year_answer(year): #defining function leap_year_answer

   if is_leap_year(year): #Checking if the year is leap year by calling is_leap_year function
           if year>2020:#Checking if the year is greater than 2020 then print message for future tense
               print("Year will be a leap year")
           else:#Otherwise print message for past tense
               print("Year was a leap year")
   else:#Otherwise the year is not a leap year
           if year>2020:#Checking if the year is greater than 2020 then print message for future tense
               print("Year will not be a leap year")
           else:#Otherwise print message for past tense
               print("Year was not a leap year")

#Below are few test inputs for the given functions
leap_year_answer(2000)
leap_year_answer(1900)
leap_year_answer(2020)
leap_year_answer(2024)
leap_year_answer(3600)
leap_year_answer(3000)

3. Please find below output screenshot of the above program. Please note that leapyear.py file was placed at D:/.

4. Note:-

i) Please note tha both the functions are placed in a single file leapyear.py present at D:/.

ii) Second function leap_year_answer(year) is using is_leap_year(year) function internally to check whether the argument year is leap year or not.

iii) Important part of the code is marked in bold.

5. Though I tried to explain the concept with comments. Still if you have any query please feel free to reach me through comments section. I will be more than happy to help you further.

6. Please upvote if you like my answer.

Thanks!!

Happy Learning!!