if a pipe flowing water has a cross sectional area nine times greater at point 2 than point 1, what would be the relation of flow of speed at the two points
Sol::
Answer is:
"The flow speed at point 1 is nine times that at point
2"
Using the continuity equation we have
A1V1=A2V2
So, as per given question, the cross-sectional area at point 2 is
nine times greater that at point 1 (i.e 9A1=A2).
So,from continuity equation
A1= 1 and A2 = 9.
=> 1*V1=9*V2
=> V1/V2=9/1
=> V1=9V2
Hence the Flow speed at point 1 is nine times that at point 2.
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