The population standard deviation for the height of high school basketball players is 3.3 inches. If we want to be 95% confident that the sample mean height is within 1.8 inch of the true population mean height, how many randomly selected students must be surveyed? Fill in the blank: n=
Answer:
Given that:
The population standard deviation for the height of high school basketball players is 3.3 inches.
population standard deviation=3.3
Margin of error,E=1.8
For 95% confidence,z=1.96
Sample size required,n=(1.96*3.3/1.8)^2
= (6.468/1.8)^2
=(3.5933) ^2
=12.91
n = 12
The population standard deviation for the height of high school basketball players is 3.3 inches. If...
The population standard deviation for the height of college basketball players is 3.2 inches. If we want to estimate 99% confidence interval for the population mean height of these players with a 0.4 margin of error, how many randomly selected players must be surveyed?
The population standard deviation for the height of college basketball players is 3.1 inches. If we want to estimate 90% confidence interval for the population mean height of these players with a 1 margin of error, how many randomly selected players must be surveyed? (Round up your answer to nearest whole number)
The population standard deviation for the height of college basketball players is 2.9 inches. If we want to estimate 99% confidence interval for the population mean height of these players with a 0.5 margin of error, how many randomly selected players must be surveyed? ____ (Round up your answer to nearest whole number)
The population standard deviation for the height of college basketball players is 3.5 inches. If we want to estimate 90% confidence interval for the population mean height of these players with a 0.9 margin of error, how many randomly selected players must be surveyed? (Round up your answer to nearest whole number)
The population standard deviation for the height of college basketball players is 3.2 inches. If we want to estimate 92% confidence interval for the population mean height of these players with a 0.8 margin of error, how many randomly selected players must be surveyed? _____ (Round up your answer to nearest whole number)
Question number 7 The population standard deviation for the height of college basketball players is 3 inches. If we want to estimate 95% confidence interval for the population mean height of these players with a 0.5 margin of error, how many randomly selected players must be surveyed? (Round us your answer to nearest whole number) I don't know
In a simple random sample of 64 households, the sample mean number of personal computers was 1.17. Assume the population standard deviation is σ = 0.23. 19) Why can we say the sampling distribution of the sample mean number of personal computers is approximately normal? 20) Construct a 98% confidence interval for the mean number of personal computers. Interpret this interval. 21) The population standard deviation for the height of high school basketball players is three inches. If we want...
1/ The height of high school basketball players is known to be normally distributed with a standard deviation of 1.75 inches. In a random sample of eight high school basketball players, the heights (in inches) are recorded as 75, 82, 68, 74, 78, 70, 77, and 76. Construct a 95% confidence interval on the average height of all high school basketball players.
the population standard deviation for the heights of dogs in inches in a city is 3.8 inches. if we want to be 95% confident that the sample mean is within 1 inch of the true population mea
A random sample of college basketball players had an average height of 63.45 inches. Based on this sample, (62.1, 64.8) found to be a 98% confidence interval for the population mean height of college basketball players. Select the correct answer to interpret this interval. We are 98% confident that the population mean height of college basketball players is between 62.1 and 64.8 inches. There is a 98% chance that the population mean height of college basketball players is between 62.1...