The population standard deviation for the height of college basketball players is 3.5 inches. If we want to estimate 90% confidence interval for the population mean height of these players with a 0.9 margin of error, how many randomly selected players must be surveyed? (Round up your answer to nearest whole number)
z critical for 90% is 1.645 [From z table]
Margin of error E = 0.90
Standard deviation sd = 3.5
sample size n = ((z*sd)/E)^2
=((1.645*3.5)/0.9)^2
= 6.3972^2
= 40.92
= 41
Sample size n = 41 (rounded)
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