Which of the following pentapeptides will exhibit the highest extinction coefficient at 280 nm? Assume that...
Which of the following pentapeptides will exhibit the highest extinction coefficient at 280 nm? Assume that each tryptophan has an extinction coefficient of 5690 M-1cm-1, tyrosine has an extinction coefficient of 1280 M-1cm-1, and the absorbance of phenylalanine at 280 nm is negligible.
| TEDSE |
| #TYWSF |
| RYYFE |
| FEWFE |
The UV-vis absorption spectrum of the peptide RYYFE collected in a 1 cm pathlength cuvette exhibits an absorbance of 0.050 at 280 nm. What is the concentration (in micromolar) of the peptide in this sample?
Homework Answers
W is tryptophan and Y is tyrosine.
Tryptophan and tyrosine has extinction coefficient of 5690 and 1280 M-1cm-1.
The pentapeptide with larger number of this two will have greater extinction coefficient.
TYWSF has 1 tryptophan and 1 tyrosine.while RYYFE has two tyrosine and FEWFE has 1 tryptophan.
Thus,TYWSF has highest extinction coefficient due to both tryptophan and tyrosine.
RYYFE has two tyrosine, so the extinction coefficient is 1290×2=2580 M-1cm-1.
We know, A=€cl
0.05=2580×c×1.
c=0.05/2580
c=1.94 E-5 M
c=19.4 micromolar.
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