A projectile is launched from a point on level ground with initial speed 15.9 miles/hour and initial angle of 50.1 degrees. Air resistance may be ignored and normal earth gravity is present. Calculate the magnitude of the final value of the horizontal component of velocity in m/s just prior to the projectile striking the ground. [Note: Don't forget to convert units as needed.]
Solution :-
Angle = 50.1°
initial speed u = 15.9 miles/hour
= 15.9 x 1609.34/3600 m/s
= 7.1079 m/s
Horizontal component of initial velocity = u cos
= 7.1079x cos50.1
= 4.56 m/s
during the projectile motion there is no change in its horizontal component of velocity
hence final horizontal component of velocity = 4.56 m/s
A projectile is launched from a point on level ground with initial speed 15.9 miles/hour and...
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