Let P(E) = 0.28, P(EF) = 0.13, and P(EFc) = 0.82. Find P(F|Ec)
Let P(E) = 0.28, P(EF) = 0.17, and P(EFc) = 0.88. Find P(F|Ec). ) 0.6071 b) 0.1667 c) 0.2361 d) 0.5862 e) 0.4286 f) None of the above.
Let P(E) = 0.28, P(E∩F) = 0.17, and P(E U Fc) = 0.88. Find P(F|Ec).
FInd the probability P(Ec) if P(E)=0.28
Given P(Ec ) = 0.43, P(F) = 0.52, and P(EF) = 0.18. Find P( E | Fc ). a) 0.8125 b) 0.7500 c) 0.5342 d) 0.9069 e) 0.3461 f) None of the above.
Let P(E)= 0.37, P(EF)= 0.19, and P(EF^c)= 0.89. Find P(F|E^C).
FC 1. Determine the algebra generated by {E, F). Let EFC 22. De Let N = 0 – 0,1 n Q, and suppose D consists of all subsets of 12 of 0, a form (a, b) n Q. Show that AD) = P(92).
2. If a silicon sample has E - Ef = 0.28 eV what is its type
and minority carrier concentration? [2 pts.]
Please only answer if you are CONFIDENT that your answer is
correct, thanks
2. If a silicon sample has Ec-Er = 0.28 eV what is its type and minority carrier concentration? [2 pts.] a. n-type; 7x10'cm*, b. p-type; 1.5x10 cm c. n-type: 3.2x10 cm d. p-type; 3.2x10 cm
5. Suppose E, F, and G are three disjoint events where P(E)- .15, P(F)- .25, and P(G).60. Find the following: (a) P(F or G) (b) P(Ec) (c) P((E or F)c) (d) P(FnG) 6. A new diagnostic test for a disease is studied. It is known whether or not these 100 individuals have the disease and the diagnostic test is administered. The results are as follows infectedhealthy tested positive tested negative 40 10 45 Let E-randomly selected person is infected and...
· + -/2 points TEAFM2 4.6.010. BM E) = 0.2. Draw a Venn diagram and find the conditional probabilities. Let P(E) = 0.35, P(F) = 0.5, and P( F (a) P(EFC) (b) P( F EC) Additional Materials eBook 2. + -12 points TEAFM2 4.6.006. EM Use the Venn diagram below to find the conditional probabilities. (a) P( EFF) (b) P( EFCF) Additional Materials
10. Prove that P(E UFUG)P(E) P(F) + 2P(EFG). 11. If P(E)9 and P(F).8, show that P(EF .7 In general, prove Bonferroni's inequality, namely, P(EF) 2 P(E) + P(F)-1 13. Prove that P(EF*)= P(E)-P(EF).