Question

This question has 6 parts. Each of the 6 parts (Part A - Part F) has...

This question has 6 parts. Each of the 6 parts (Part A - Part F) has a dropdown list of possible answers. Choose the best answer from the dropdown list for EACH part of the question below.  

The same psychiatrists are now interested in determining if there is any difference in depression levels of participants before and after a group therapy program. Depression levels of a sample of participants both before and after the program are listed below:

Patient # Depression level before group therapy program (X1) Depression levels after group therapy program (X2)
1 68 62
2 76 72
3 54 55
4 89 82
5 62 65

You are informed the estimated standard error of the mean differences (s) is 1.96

Using the appropriate two-tailed hypothesis test (a two related samples t-test) with the H0: µD = 0 and H1: µD   0, calculate the test statistic and make a decision about the null hypothesis using an alpha (α) level of 0.05.

You will use the information above to complete the question parts below for a two related samples t-test.

Part A: What is the degrees of freedom (df) associated with your test?

PART A ANSWER:                            [ Select ]                       ["4", "9", "8", "6", "3"]      

Part B: Which of the following represents the appropriate critical value(s), testing at an alpha level (α) of 0.05?

PART B ANSWER:                            [ Select ]                       ["-4.032", "-2.021 and 2.021", "-1.96 and 1.96", "-2.776 and 2.776", "2.331 and -2.331"]      

Part C: Calculate the sample mean of difference scores which

you will use in the calculation of your test statistic):?

PART C ANSWER:                            [ Select ]                       ["2.1", "3.9", "1.6", "2.6", "3.4"]      

Part D:What is the t-statistic associated with your test? (rounded to the nearest hundredth) - see note above for the value of the standard error of the mean differences.

PART D ANSWER:                            [ Select ]                       ["2.92", "2.26", "3.56", "1.97", "1.33"]      

Part E: Given your test results, what is your decision about the null hypothesis?

PART E ANSWER:                             [ Select ]                       ["Reject the null", "Fail to reject (e.g., retain) the null"]      

Part F: The best interpretation of the appropriate decision regarding the null hypothesis would be: "Based on our study, we                            [ Select ]                       ["have", "do NOT have"]         enough evidence to conclude that there appears to be a difference in the mean depression levels of the population of people before and after the group therapy program."

  

0 0
Add a comment Improve this question Transcribed image text
Answer #1

Part A: What is the degrees of freedom =4

Part B: Which of the following represents the appropriate critical value 2.776

Part C: Calculate the sample mean of difference scores =2.6

Part D:What is the t-statistic =1.33

PART E ANSWER Fail to reject  

Part F: do NOT have

Add a comment
Know the answer?
Add Answer to:
This question has 6 parts. Each of the 6 parts (Part A - Part F) has...
Your Answer:

Post as a guest

Your Name:

What's your source?

Earn Coins

Coins can be redeemed for fabulous gifts.

Not the answer you're looking for? Ask your own homework help question. Our experts will answer your question WITHIN MINUTES for Free.
Similar Homework Help Questions
  • A school counselor in a high school would like to try out a new conflict-resolution program...

    A school counselor in a high school would like to try out a new conflict-resolution program to change aggressiveness in students. She first surveyed 16 students using a 20-item instrument to measure their levels of aggression (on a scale of 0 to 10, with higher numbers meaning higher aggression levels). One month after the conflict resolution program was implemented, the students were given the same survey. The data are listed in the table below. The school counselor/researcher has set the...

  • a= .05 A therapist would like to evaluate the effectiveness of a procedure for treating depression....

    a= .05 A therapist would like to evaluate the effectiveness of a procedure for treating depression. A sample of n = 16 depressed clients is obtained and each person’s level of depression is measured using a standardized questionnaire before they begin the therapy program. Two weeks after therapy, each client’s level of depression is measured again. The average level of depression dropped by 6.8 points following therapy. The difference scores had a variance of 64. a. State the null hypothesis....

  • A psychologist would like to evaluate the effect of Cognitive-Behavioral Therapy and antidepressant use on depression....

    A psychologist would like to evaluate the effect of Cognitive-Behavioral Therapy and antidepressant use on depression. He obtains 10 clinical participants for a period of 2 months. During the first month, the participants are given no therapy; half the participants are given an anti-depressant and the other half receive a placebo. This is followed by a diagnostic Depression test (0-10). During the second month, those same participants continue treatment, but now all receive CBT. This is then again followed by...

  • Researchers wanted to know if the levels of algae in a pond were hazardous to the...

    Researchers wanted to know if the levels of algae in a pond were hazardous to the fish that lived there. If the average levels are above 30 parts per million (ppm) the pond would be considered hazardous to the health of the fish. In the study with a 5% significance level, researchers collected data and found that the sample mean from 60 samples was 30.829. If σ = 34 , H 0:   m u = 30 ; H a: μ <...

  • A group of 20 patients is given the medication lipitor for four weeks to reduce their...

    A group of 20 patients is given the medication lipitor for four weeks to reduce their cholesterol levels. The before mean value was 224 with a standard deviation of 15.3. After four weeks the same 20 patients had a mean cholesterol level of 203 with a standard deviation of 12.7. The mean of the difference is 21 with a standard deviation of 6.1. Test the hypothesis that there is no difference versus the alternative hypothesis that Lipitor is reducing the...

  • A clinical trial is run to assess the effects of different forms of regular exercise on HDL level...

    A clinical trial is run to assess the effects of different forms of regular exercise on HDL levels in a sample of healthy men between the ages of 18 and 29. Participants in the study were randomly assigned to either one of three exercise groups (Weight training, Aerobic exercise or Yoga) or to a control group in which they were assigned to a regular exercise program. Participants were instructed to follow the program for 8 weeks. Their HDL levels were...

  • Question 2 The primary advantage of the related samples design is that it controls for ________...

    Question 2 The primary advantage of the related samples design is that it controls for ________ that may artificially increase the observed differences between means in other types of studies. Group of answer choices degrees of freedom MD individual differences the effect of the treatment Question 3 A manager would like to know if the performance of sales representatives significantly (α = .05) improves over the first 6 months of employment. For 5 new sales representatives, the number of sales...

  • Question 3 (25 points) A study is being conducted to determine whether a particular exercise program...

    Question 3 (25 points) A study is being conducted to determine whether a particular exercise program is effective at reducing the mean blood cholesterol level on males between the ages of 35 and 50. Six subjects participated in the program, and their cholesterol levels before and after the program are as follows. 1 Blood Cholesterol Level Subject Before After 265 229 2 240 231 3 258 227 4 295 240 5 251 238 6 225 226 Using this data, we...

  • Can taking chess lessons and playing chess improve memory? The online article described a study in...

    Can taking chess lessons and playing chess improve memory? The online article described a study in which sixth-grade students who had not previously played chess participated in a program in which they took chess lessons and played chess daily for 9 months. Each student took a memory test (the Test of Cognitive Skills) before starting the chess program and again at the end of the 9-month period. The table below shows the results for 12 randomly selected students. Student 1...

ADVERTISEMENT
Free Homework Help App
Download From Google Play
Scan Your Homework
to Get Instant Free Answers
Need Online Homework Help?
Ask a Question
Get Answers For Free
Most questions answered within 3 hours.
ADVERTISEMENT
ADVERTISEMENT
ADVERTISEMENT