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Both HBr(g) and Kr(g) have similar molar masses (81 g/mol and 84 g/mol, respectively). Their boiling...

Both HBr(g) and Kr(g) have similar molar masses (81 g/mol and 84 g/mol, respectively). Their boiling points, however, are very different.

a) Which intermolecular force would be expected to have the same strength in these two chemicals?

b) Why are the boiling points so different?

c) Which chemical do you expect to have the higher boiling point?

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Answer #1

a)

Since molar mass is same for both, London dispersion forces would be same for both

Answer: London dispersion

b)

HBr is polar and hence it has stronger dipole-dipole forces whereas Kr only has London dispersion forces.

Thats why boiling point of HBr is greater

C)

HBr

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