Consider the following chemical equation for the reaction of iodine and chlorine.
I2(g)+Cl2(g)⇌2ICl(g)
How will the position of the equilibrium change if the volume of the vessel in which the reaction is contained increases?
I2 (g) + Cl2 (g) = 2 ICl (g)
At equilibrium , when we change the volume ( here we are decreasing )
On decreasing the volume equilibrium shift towards the less number of moles of gas side.
Here both side gas molecules are same (2 molecule ) no shifting occurs.
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Consider the following chemical equation for the reaction of iodine and chlorine. I2(g)+Cl2(g)⇌2ICl(g) How will the...
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