Question

Review: Molecular weight and Avogadro number. Fill in table and show equations on a separate sheet. The first row is an example.

Mass in g	Molar mass in g/mol	Moles in mol	Avogadro number	# of particles
46.0 g Na	23 g/mol	2.00 mol Na	6.022 ´ 10 23 particles/mol	1.204 ´ 10 24 NaCl
		2.00 mol O2
110 g CO2
				6.022 ´ 10 22H2O
		0.25 mol NH3
37.0 kg C4H10
				1.204 ´ 10 23H2

Answer 1

Mass in gm	Molar mass in g/mol	Moles in mol	Avogadro number	# of particles
46.0 g Na	23 g/mol	2.00 mol Na	6.022 x1023	1.204x1024 of Na
64 g	32g/mol	2.00 mol O2	6.022 x1023	1.204x1024 of O2
110 g CO2	44.01 g/ mol	2.499 mol CO2	6.022 x1023	1.5054 x 1024 of CO2
4.257 g of NH3	17.03 g/mol	0.25 mol NH3	6.022 x1023	1.505 x 1023 of NH3

1.8 g of H2O	18.02 g/mol	0.01 Mol H2O	6.022 x1023	6.022 x 1022 of H2O
37.0 kg C4H10	58.12 g/mol	636.61 mol C4H10	6.022 x1023	3.834 x 1025 of C4H10
0.403 g of H2	2.016 g/mol	0.1999 Mol of H2	6.022 x1023	1.204x 1023 of H2

Question 1

Moles of O2 = 2 g

Molar mass of O2 =  32g/mol

Mass of O2 = 2 g x 32g/mol = 64 g

Avogadro number =  6.022 x1023 particles/mol

No of particle = 2 mol x 6.022 x1023  particles/mol = 1.204 x 1024 particles

Question 2

Mass of CO2 = 110 g

Molar mass of CO2 =  44.01 g/mol

Moles of CO2 = 110 g / 44.01 g/mol = 2.499 Moles

Avogadro number =  6.022 x1023 particles/mol

No of particle = 2.499 Mol x 6.022 x1023  particles/mol = 1.5054 x 1024 of CO2 particles