A submarine can withstand an external pressure of 63 atm before collapsing. If seawater has a density of 1027 kg/m^3 how deep can the sub dive?
here,
63 atm = 6.38 MPa
Assuming the sub has 1 atm of air pressure internally, which cancels the 1 atm of pressure from the atmosphere.
pressure in Pa = weight of a column of water 1 m^2 in cross
section and H meters high
weight of that column = volume x density = 1 m^2 x H m x 1027
kg/m^3 x 9.8 N/kg
P = H x 1027 x 9.8 N = 10064H N
10064 * H N = 6.38e6 Pa
H = 634 m
the maximum depth is 634 m
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