Calculate the pH of a solution that is 0.0060 M in HClO4 and 0.0060 M in...

Question

Question

Calculate the pH of a solution that is 0.0060 M in HClO4 and 0.0060 M in HCN. Ka of HCN is 6.2 × 10−10.

Answer 1

Answer #1

Since HClO₄ is a strong acid, it is completely dissociated to form H⁺(aq) and ClO₄^-(aq).

Hence [H⁺(aq)] due to HClO₄ = [HClO₄] = 0.0060 M

Since HCN is a very weak acid with a very small value of Ka, H⁺(aq) formed due to its dissociation is very small.

Hence we can neglect [H⁺(aq)] due to dissociation of HCN.

Hence total [H⁺(aq)] = 0.0060 M

=> pH = - log[H⁺(aq)] = - log[0.0060] = 2.22 (Answer)

Answer 2

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