Assume that when adults with smartphones are randomly selected, 58% use them in meetings or classes. If 13 adult smartphone users are randomly selected, find the probability that fewer than 5 of them use their smartphones in meetings or classes.
This is a binomial distribution
p = 0.58
n = 13
P(X = x) =13Cx * 0.58x * (1 - 0.58)13-x
P(X < 5) = P(X = 0) + P(X = 1) + P(X = 2) + P(X = 3) + P(X = 4)
= 13C0 * 0.580 * 0.4213 + 13C1 * 0.581 * 0.4212 + 13C2 * 0.582 * 0.4211 + 13C3 * 0.583 * 0.4210 + 13C4 * 0.584 * 0.429
= 0.0446
Assume that when adults with smartphones are randomly selected, 58% use them in meetings or classes....
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