Assume that when adults with smartphones are randomly selected, 42 % use them in meetings or classes. If 13 adult smartphone users are randomly selected, find the probability that fewer than 4 of them use their smartphones in meetings or classes.
The probablity is _______
(Type an integer or decimal rounded to four decimal places as needed.)
SOLUTION :
p = adults with smartphones = 42% = 0.42
q = adults without smartphones = 1 - 0.42 = 0.58
As per binomial distribution : For n = 13 :
P(x < 4)
= P(0) + P(1) + P(2) + P(3)
= ncr(13, 0)*(0.42)^0 *(0.58)^13 +ncr(13, 1)*(0.42)*(0.58)^12+ ncr(13, 2)*(0.42)^2 * (0.58)^11 + ncr(13, 3)*(0.42)^3 * (0.58)^10
= 0.1344 (ANSWER).
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