A spring of force constant 2 N/m has an empty bird cage of mass 0.28 kg...
A spring of force constant 2 N/m has an empty bird cage of mass 0.28 kg at its end, vibrates at SHM. A 2 kg bird flies into the moving cage and rests in it, the period of vibration changes from the original period (when the cage was empty). What is the period before and after the presence of the bird?
Homework Answers
The period of SHM is given by
where m is the mass attached to the spring and k is the spring constant.
here given
k=2N/m
The mass attached to the spring before a bird flies into the cage is 0.28kg.so the time period of the SHM before the presence of the bird is
The mass attached to the spring after a bird flies into the cage is 0.28kg+2kg=2.28Kg.so the time period of the SHM after the presence of the bird is
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