What is the total solubility of a weak acid (S) when pH of the solution equals...
- What is the total solubility of a weak acid (S) when pH of the solution equals to the pKaof the weak acid. Its So is 0.01M?
Homework Answers
Solution:
Suppose weak acid is HA. It dissociated as,
HA === H+ + A-
0.01 M --------0
(0.01 - X) ------ X
According to Hendersen equation,
pH = pka + log [A-] / [HA]
When, pH = pka, then
log [A-] / [HA] = 0
Hence,
[A-] / [HA] =1
Thus, X/ (0.01 -X) = 1
2X = 0.01
X = 0.05 M
When, pH = pka for a weak acid, then acid is half ionized. Thus,
S = 0.01 M /2 = 0.05 M = 0.05 mol/L
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