Question

An object is placed 22.6 cm to the left of a diverging lens (f = -1.08 cm). A concave mirror (f = 16.0 cm) is placed 24.8 cm to the right of the lens to form an image of the first image formed by the lens. Find the final image distance, measured relative to the mirror. (b) Is the final image real or virtual? (c) Is the final image upright or inverted with respect to the original object?

(a) Number

(b) Final image is

(c) Final image is

Answer 1

a)

From thin lens equation

1/f = 1/di + 1/do

For First lens

=>1/(-1.08) = 1/di,1 + 1/22.6

di,1 =-1.030743243 cm

The Object distance for second lens

do,2 = 24.8-1.030743243 = 23.77 cm

Therefore

=>1/16 = 1/23.77 + 1/di.2

di.2=48.95 cm

b)

Real ,Since image distance is positive

c)

Inverted