Question

please answer all parts of the question:

1.An object is placed 21.3 cm to the left of a diverging lens (f = -9.51 cm). A concave mirror (f = 10.6 cm) is placed 30.8 cm to the right of the lens to form an image of the first image formed by the lens. Find the final image distance, measured relative to the mirror. (b) Is the final image real or virtual? (c) Is the final image upright or inverted with respect to the original object?

Answer 1

First find the image from the lens:

According to lence formula,

1/s' + 1/s = 1/f......... (1)

1/s' = 1/f - 1/s

               = 1/(-9.51) - 1/21.3

    ∴ s' = - 6.574 cm (image is to the left of the lens)

So the object for the mirror is 6.574 + 30.8 = 37.3745 cm

From equation (1),

1/s' = 1/f - 1/s

1/s' = 1/10.6 - 1/37.3745

s' = 14.79 cm from the mirror

virtual and inverted