Calculate the water potential of a cell with no cell wall that has 0.5 M sugar...

Question

Question

Calculate the water potential of a cell with no cell wall that has 0.5 M sugar solute concentration at 25C sea level

Answer 1

Answer #1

Water potential = solute potential + presssure potential

Solute potential = nCRT

n is ionozation constant = nothing about solute is given, so we will assume n to be 1

C is concentration of solute in molar = 0.5

R is gas constant 0.0831

T is temperature = 25℃ = 298 K

Pressure potential is taken to be 0.

So, water potential = solute potential

= (1)(0.5)(0.0831)(298) = 12.3819 Pa

Water potential = 12.39 Pa

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Answer 2

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