the molar entropies of carbon monoxide and carbon dioxide at 25C are 197.7 and 213.8 J/Mol*k...
the molar entropies of carbon monoxide and carbon dioxide at 25C are 197.7 and 213.8 J/Mol*k respectively. How many times more accessible microstates does CO2 have than CO at 25C
Homework Answers
The molar entropy in terms of micro-state is given as :
S=KB*lnΩ
S=entropy
KB=Boltzmann Constant=1.38*10-23J/K
Ω=number of microstates
Given,
Molar entropy of CO = 197.7 J/molK
Molar entropy of CO2 = 213.8 J/molK
Suppose for 1 mole of CO and CO2, then the entropy will be :
S(CO) = 197.7 J/molK × 1 mol
S(CO) = 197.7 J/K
S(CO2) = 213.8 J/molK × 1 mol
S(CO2) = 213.8 J/K
ln Ω(CO)=S(CO)÷KB
ln Ω(CO2)=S(CO2)÷KB
Dividing these two equations we get,
ln Ω(CO2)÷ln Ω(CO)=S(CO2)÷S(CO)
ln Ω(CO2)÷ln Ω(CO)=213.8÷197.7=1.08
ln Ω(CO2)=1.08*ln Ω(CO)
So 1.08 times more
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