Consider a solution of 0.31 M C5H5N (Kb = 1.7×10-9). Decide if each of the following is a major or minor species in the solution. Calculate the pH of this solution.
Consider a solution of 0.31 M C5H5N (Kb = 1.7×10-9). Decide if each of the following...
What is the pH of a .62 M [C5H5NH]NO3 solution? Kb(C5H5N) = 1.7 x 10-9 Kb(NH3) = 1.8 x 10-5
16 What is the pH of a 1.63 M solution of pyridine (C5H5N; Kb = 1.7 x 10-9)? [ (4 Puan) 9.72 10.07 9.07 5.23 8.77
Calculate the pH of a 0.20 M solution of the weak base pyridine. (C5H5N; Kb = 1.7 x 10-9). What is the pH of a 0.20 M solution of NH4Cl? [Kb(NH3) = 1.8 ´ 10–5]
Find the [OH−] of a 0.40 M pyridine (C5H5N) solution. (The value of Kb for pyridine (C5H5N) is 1.7×10−9.) Find the pH of a 0.40 M pyridine (C5H5N) solution.
A 0.162 molar C5H5N solution has been prepared (Kb= 1.7×10^-9). what is [C5H5N] after equilibrium occurs?
30.0 mL of 0.340M C5H5N (Pyridine Kb = 1.7 x 10-9) is titrated with 0.190M HBr (hydrobromic acid). Determine the pH at each of the following points. a. Before any HBr is added b. After 3.00mL of HBr is added c. at half titration d. at equivalence e. After 0.50 mL of HBr added after the equivalence point
What is Ka for the conjugate acid of C5H5N (Kb = 1.7 x 10 9)? 7 3 LO 89 +/- X 100
Determine the pOH of a 0.098 M C5H5N solution at 25°C. The Kb of C5H5N is 1.7 × 10-8. A. A) 4.59 B. B) 9.41 C. C) 3.71 D. D) 4.39 E. E) 4.67 F. F) 1.34 G. G) none of these
Kb = 1.7x10–9 for C5H5N (pyridine). What would be the pH of an aqueous solution containing 0.093 M C5H5N and 0.18 M C5H5NH+?
You have four solutions below. a) pure water b) 0.400M solution of C5H5N and 0.250 M C5H5NHBr c) 0.500M solution of C5H5NHBr d) 0.500M solution of pyridine, C5H5N. (Kb=1.7 x 10-9) Find the pH of a, b, and d. Show all work with steps.