Problem 12-18 (Algorithmic)
A building contractor is preparing a bid on a new construction project. Two other contractors will be submitting bids for the same project. Based on past bidding practices, bids from the other contractors can be described by the following probability distributions:
Contractor | Probability Distribution of Bid |
A | Uniform probability distribution between $590,000 and $790,000 |
B | Normal probability distribution with a mean bid of $690,000 and a standard deviation of $49,000 |
If required, round your answers to three decimal places.
As Contractor A bid follows a uniform distribution, the probability that the bid is more than contractor A is:
P(A) = (730000 - 590000)/(790000 - 590000)
P(A) = 0.7
As Contractor B bid follows a normal distribution, the probability that the bid is more than contractor B is:
P(z<=x) where z = (730000 - 690000)/49000
z = 0.816
Hence, P(z<=x) = P(B) = 0.792
Therefore, probability of winning the bid of $730,000 = P(A). P(B) =0.7*0.792 = 0.555
B) Doing the same procedure for the bid of 755000,
P(A) = 0.825
P(B) = 0.907
P(winning the bid of $755,000)= 0.749
The probability of winning the bid of $765000 = P(A). P(B) = 0.875 * 0.937 = 0.820
The recommendation would be to choose the bid of $755000.
Problem 12-18 (Algorithmic) A building contractor is preparing a bid on a new construction project. Two...
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