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How much water must be added to 30 liters of a 75% salt solution to reduce it to 15%

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How much water must be added to 30 liters of a 75% salt solution to reduce it to 15%?
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Answer #1
How much water must be added to 30 liters of a 75% salt solution to reduce it to 15%? . Let x = liters of water added then .75(30) = .15(30+x) 22.5 = 4.5 + .15x 18 = .15x 120 liters = x
answered by: AP Physics
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Answer #2
How much water must be added to 30 liters of a 75% salt solution to reduce it to 15%? : Let x = amt of water required to this : the amt salt remains the same, only the % salt changes A simple equation : .75(30) = .15(x + 30) : 22.5 = .15x + 4.5 : 22.5 - 4.5 = .15x : 18 = .15x x = {{{18/.15}}} x = 120 liters of water required : : Check solution original equation (equal amt of salt) .75(30) = .15(120 + 30) 22.5 = .15(150) 22.5 = 22.5 ; : Did this unconfuse you somewhat
answered by: neasha
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