How much water must be added to 40.0 g of CaCl2 to produce a solution that...
How much water must be added to 40.0 g of CaCl2 to produce a solution that is 35.0 wt% CaCl2?
Homework Answers
35% = weight CaCl2/(weight water + weight CaCl2) * 100
weight CaCl2 = 40
let weight water = x
35 = 40/(x + 40) * 100
0.35(x + 40) = 40
0.35x = 26
x = 74.28 gram water must be added to 40.0 g of
CaCl2 to produce a solution that is 35.0 wt% CaCl2
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