Consider the following scenario: There are three cups which are turned upside down. Beneath two of...
Consider the following scenario: There are three cups which are turned upside down. Beneath two of the cups is a piece of chocolate; the last cup has nothing underneath it. You are free to choose which cup you want to turn over. What is the probability that you will first choose a cup with chocolate then, on the next choice, choose the second cup with chocolate? (After the first cup is turned over, it is not replaced.)
Homework Answers
P(First choose a cup with chocolate then, on the next choice, choose the second cup with chocolate)
= P(First cup chocolate)*P(Second cup chocolate | First cup chocolate)
= (2/3)*(1/2)
= 1/3
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