The silicon monosulfide diatomic molecule (SiS(g)) has a
bond
dissociation enthalpy (BDE) of 619 kJ mol-1 , an
inter-nuclear distance of
193 pm and an electronic dipole moment ( el ) of 1.73 Debyes.
a) Calculate the partial ionic character for SiS(g).
b) Compare the molecular orbital descriptions for the bonding in
SiS (g)
Si2 (g) and S2 (g).
Given, dipole moment (observed) = 1.73 Debyes = 1.73 X 3.33564 X 10−30 C·m = 5.77 X 10-30 C.m
We know that dipole moment = electronic charge X interatomic distance
Now if the bond is 100% polarized then, dipole moment (100%) = (1.6 X 10−19) C X (1.41 X 10−10) m = 2.26 X 10−29 C m
ionic character = dipole moment (observed) /dipole moment (100%) = (5.77 X 10-30) / (2.26 X 10−29) = 0.26
% ionic character = 0.26 X 100 = 26%
For question b), it is too long to describe here. You need to draw three molecular orbital diagrams and probably you will also need to calculate the bond orders.
The silicon monosulfide diatomic molecule (SiS(g)) has a bond dissociation enthalpy (BDE) of 619 kJ mol-1...