Assume that adults have IQ scores that are normally distributed with a mean of
95.4
and a standard deviation of
25
Find the probability that a randomly selected adult has an IQ greater than
142.7
(Hint: Draw a graph.)
Solution :
Given that,
mean = = 95.4
standard deviation = =25
P (x > 142.7 )
= 1 - P (x < 142.7 )
= 1 - P ( x - / ) < ( 142.7 - 95.4 / 25)
= 1 - P ( z < 47.3 / 25 )
= 1 - P ( z < 1.89 )
Using z table
= 1 - 0.9706
= 0.0294
Probability = 0.0294
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