A thin flake of transparent material (n = 1.44) is used to cover one slit of a double-slit interference arrangement. The central point on the screen is now occupied by what had been the 3th bright side fringe (m = 3). If λ = 574 nm, what is the thickness of the flake in meters?
in a double slit normally the path difference = d sin
in this case 1 slit is covered by snow of thickness t (say), due to this additional path difference = t (n-1)
total path difference = d sin
+ t x (n-1)
for location of original central maximum ,
=0
so at
= 0 , total path difference = 0+ t (n -1)= m x
= 3 x 574 x 10^(-9) m ( since m=3)
t = 3 x 574 x 10^(-9) m / (1.44 - 1)= 3.91 micro meters
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A thin flake of transparent material (n = 1.44) is used to cover one slit of...
A thin flake of mica (n = 1.58) is used to cover one slit of a
double-slit interference arrangement.The central point on the
viewing screen is now occupied by what had been the seventh bright
side fringe (m = 7). If = 550 nm, what
is the thickness of the mica?
A thin flake of mica (n = 1.58) is used to cover one slit of a double-slit interference arrangement. The central point on the viewing screen is now occupied...
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A laser beam strikes a double slit with a slit spacing of 1.5E-5 m. The slit-to- screen distance is 2.0 m. The first bright interference fringe is located 7 cm above the middle of the central bright maximum. What is the wavelength of the laser light? O 525 nm O 373 nm 454 nm 667 nm 702 nm
A laser beam strikes a double slit with a slit spacing of 1.5E-5 m. The slit-to-screen distance is 2.0 m. The first bright interference fringe is located 7 cm above the middle of the central bright maximum. What is the wavelength of the laser light? 525 nm 373 nm O 454 nm 667 nm O 702 nm
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