Consider the reaction 2H2(g)+O2(g)→2H2O(l) What is the mass of water, H2O(l), produced when 5.20 g of O2(g) reacts with excess H2(g)? PLEASE HELP
2H2 (g) + O2 (g) 2H2O (l)
Mole ratio of H2 , O2 and H2O = 2 :1 :2
Molar mass of H2O = 18 g/mol
Molar mass of H2 = 2 g/mol
Molar mass of O2 = 32 g/mol
So, 32 g O2 gas reacts with excess H2 to give 2×18 g H2O.
Conversion factor =
then, 5.20 g O2 gas reacts with excess H2 (g) to give
5.20 (g) ×
= 5.85 g H2O (l).
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