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Consider the reaction 2H2(g)+O2(g)→2H2O(l) What is the mass of water, H2O(l), produced when 5.20 g of...

Consider the reaction 2H2(g)+O2(g)→2H2O(l) What is the mass of water, H2O(l), produced when 5.20 g of O2(g) reacts with excess H2(g)? PLEASE HELP

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Answer #1

2H2 (g)  + O2 (g)   2H2O (l)

Mole ratio of H2 , O2 and H2O  = 2 :1 :2

Molar mass of H2O = 18 g/mol

Molar mass of H2 = 2 g/mol

Molar mass of O2 = 32 g/mol

So, 32 g O2 gas reacts with excess H2 to give 2×18 g H2O.

Conversion factor =

then, 5.20 g O2 gas reacts with excess H2 (g) to give

5.20 (g) ×

= 5.85 g H2O (l).

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